Find the angles, θ<0<360, that satisfy the equation below, to the nearest 10th of a degree. sin(θ)= -√11/5

asked Jul 18, 2022 153k views

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Find the angles, θ<0<360, that satisfy the equation below, to the nearest 10th of a degree.

sin(θ)= -√11/5

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Answer:

$\sin( \theta) = - ( √(11) )/(5) \\ \theta = \sin {}^( - 1) ( - ( √(11) )/(5) ) \\ \theta = 41.6 \degree, \: 221.6 \degree, \: 318.4 \degree$

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