Question

Find the angles, θ<0<360, that satisfy the equation below, to the nearest 10th of a degree.

cos(θ)= -√7/5

Answer 1

9514 1404 393

Answer:

121.9°, 238.1°

Explanation:

One angle is found directly from ...

θ = arccos(-√7/5) ≈ 121.9°

The other angle is this subtracted from 360°:

θ = 360° -121.9° = 238.1°

The two angles are 121.9° and 238.1°.