Question

Factorise 4a^2+b^2-4ab-8a+4b+4​

Answer 1

The factorized form of the given expression is
`4 [(a-1)^2 - b(a - 1 + (b)/(4))]`

Explanation:

Given;

4a² + b² - 4ab - 8a + 4b + 4

This expression is factorized as follows;

(4a² - 8a + 4) + (b² - 4ab + 4b)

(4a² - 4a - 4a + 4) + b² - 4b(a - 1)

(4a - 4)(a - 1) + b² - 4b(a - 1)

(4a - 4)(a - 1) - 4b(a - 1) + b²

4(a - 1)(a - 1) - 4b(a - 1) + b²

4(a - 1)² - 4b(a - 1 + b/4)

`4(a- 1)^2 - 4b(a - 1 + (b)/(4) )\\\\4 [(a-1)^2 - b(a - 1 + (b)/(4))]`