Question

please help me with Chem I ONLY HAVE 5 MINUTES if methane gas (CH4) flows at a rate of 0.25L/s, how many grams of methane gas will there be in a room after 1 hour of time has passed?​

Answer 1

643g of methane will there be in the room

Step-by-step explanation:

To solve this question we must, as first, find the volume of methane after 1h = 3600s. With the volume we can find the moles of methane using PV = nRT -Assuming STP-. With the moles and the molar mass of methane (16g/mol) we can find the mass of methane gas after 1 hour as follows:

Volume Methane:

3600s * (0.25L / s) = 900L Methane

Moles methane:

PV = nRT; PV / RT = n

Where P = 1atm at STP, V is volume = 900L; R is gas constant = 0.082atmL/molK; T is absolute temperature = 273.15K at sTP

Replacing:

PV / RT = n

1atm*900L / 0.082atmL/molK*273.15 = n

n = 40.18mol methane

Mass methane:

40.18 moles * (16g/mol) =

643g of methane will there be in the room