Question

Find the equation of the line parallel to y=-11-5, that passes through the point

(4, -3). Write your answer in slope-intercept form. Do not use spaces in your
answer. Enter any fractions like a/b or-a/b.

Answer 1

y=41−11x

Explanation:

The equation of the line in the slope-intercept form is y=5−11x.

The slope of the parallel line is the same: m=−11.

So, the equation of the parallel line is y=−11x+a.

To find a, we use the fact that the line should pass through the given point: −3=(−11)⋅(4)+a.

Thus, a=41.

Therefore, the equation of the line is y=41−11x.

Answer 2

y=41−11x

Explanation:

The equation of the line in the slope-intercept form is y=5−11x.

The slope of the parallel line is the same: m=−11.

So, the equation of the parallel line is y=−11x+a.

To find a, we use the fact that the line should pass through the given point: −3=(−11)⋅(4)+a.

Thus, a=41.

Therefore, the equation of the line is y=41−11x.

Answer: y=41−11x.