Question

If 22.5 mol of an ideal gas occupies 30.5 L at 447 K, what is the pressure of the gas?

pressure:
_______________________ atm

Answer 1

P = 27.07 atm

Step-by-step explanation:

Given that,

The number of moles, n = 22.5 mol

Volume, V = 30.5 L

Temperature, T = 447 K

We need to find the pressure of the gas. The ideal gas law is as follows :

`PV=nRT\\\\P=(nRT)/(V)`

R = 0.0821 L-atm/mol-K

Put all the values,

`P=(22.5* 0.0821* 447)/(30.5)\\\\P=27.07\ L`

So, the pressure of the gas is 27.07 atm.