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1. Find the equations of the following lines.

a. The line that passes through points A(-1,1) and B(3,0).​

User Cmaher
by
6.9k points

1 Answer

2 votes

Answer:


y = -(1)/(4)x + (3)/(4)

Explanation:

First, find the slope. The slope can be found by using the following equation:

slope
m = (y_2 - y_1)/(x_2 - x_1)

Let:


(x_1 , y_1) = (-1 , 1)\\(x_2 , y_2) = (3 , 0)

Plug in the corresponding numbers to the corresponding variables:


m = (y_2 - y_1)/(x_2 - x_1) = (0 - 1)/(3 - (-1)) = (-1)/(3 + 1) = -(1)/(4)

Plug in
-(1)/(4) into the equation for slope:

y = mx + b

Note that:

y = y

m = slope

x = x

b = y-intercept


y = -(1)/(4)x + b

Plug in a point into the equation. In this case, I will use b(3 , 0). Remember (x , y):


0 = -(1)/(4)(3) + b \\0 = -(1 * 3)/(4) + b\\0 = -(3)/(4) + b\\0 (+(3)/(4)) = -(3)/(4) (+(3)/(4)) + b\\b = (3)/(4)

Equation:


y = -(1)/(4)x + (3)/(4)

User Kslstn
by
7.1k points