Question

2. A jack exerts a vertical force of 4.5 X 103

newtons to raise a car 0.25 meter. How much
work is done by the jack?

Answer 1

Correct Question:-

A jack exerts a vertical force of 4.5 × 10³

newtons to raise a car 0.25 meter. How much

work is done by the jack?

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Given :-

`\star \sf \small force = 4.5 * {10}^(3) \: newton`

`\star \sf \small distance = 0.25 \: meter`

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To find:-

`\sf \star \: work = \: ?`

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Solution:-

we know :-

`\bf \dag \boxed{ \rm work = force * distance}`

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So:-

`\dashrightarrow \sf work = force * distance`

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`\dashrightarrow \sf work = (4.5 * 1 {0}^(3) ) * 0.5 \\`

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`\dashrightarrow \sf work = (4.5 * 1 {0}^(3) ) * (0 \cancel.5)/(10) \\`

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`\dashrightarrow \sf work = (4.5 * 1 {0}^(3) ) * (5)/(10) \\`

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`\dashrightarrow \sf work = (4.5 * 1 {0}^(3) ) * \cancel (5)/(10) \\`

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`\dashrightarrow \sf work = (4\cancel.5)/(10) * 1 {0}^(3) * (1)/(2) \\`

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`\dashrightarrow \sf work = (45)/(10) * 1 {0}^(3) * (1)/(2) \\`

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`\dashrightarrow \sf work = \frac{45}{10 {}^(0) } * 1 {0}^(3 - 1) * (1)/(2) \\`

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`\dashrightarrow \sf work = \frac{45}{10 {}^(0) } * 1 {0}^(2) * (1)/(2) \\`

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`\dashrightarrow \sf work = (45)/(1) * 1 {0}^(2) * (1)/(2) \\`

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`\dashrightarrow \sf work = \frac{45 * 10 * \cancel{10}}{ \cancel2} \\`

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`\dashrightarrow \sf work = (45 * 10 * 5)/( 1) \\`

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`\dashrightarrow \sf work =225 * 10`

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`\dashrightarrow \bf work =\red{2250\: joule}`