113k views
5 votes
What is an equation of the line that passes through the points (-2,7) and (1, -8)?

User Bgw
by
3.4k points

2 Answers

4 votes

Answer:

y=-5x-3

Explanation:

m=(y2-y1)/(x2-x1)

m=(-8-7)/(1-(-2))

m=-15/(1+2)

m=-15/3

m=-5

y-y1=m(x-x1)

y-7=-5(x-(-2))

y-7=-5(x+2)

y=-5x-10+7

y=-5x-3

User Eoin
by
4.0k points
4 votes

Answer:

y=-5x-3

Explanation:

You need to plug both of them into the equation

y=mx+b

This would give us

7=m(-2)+b

-8=m+b

15=-3m

m=-5

y=-5x-3

User Johnjamesmiller
by
2.9k points