Question

A gyroscope slows from an initial rate of 34 rad/s at a rate of 0.619 rad/s2. The angular displacement when it stops moving is _

Answer 1

Answer:
`933.76\ rad`

Step-by-step explanation:

Given

The initial rate of gyroscope is
`\omega_o=34\ rad/s`

Angular deceleration
`\alpha =0.619\ rad/s^2`

Using angular equation of motion

`\Rightarrow \omega^2-\omega_o^2=2\alpha \theta`

Insert the values

`\Rightarrow 0-34^2=2(-0.619)\theta \\\\\Rightarrow \theta =(34^2)/(2* 0.619)\\\\\Rightarrow \theta =933.76\ rad`

Thus, the angular displacement is
`933.76\ rad`