Question

What is the electric field at a point

0.300 m to the right of a
-4.77*10^-9 C charge?
Include a + or - sign to indicate the
direction of the field.

Answer 1

E = -477 N/C

Step-by-step explanation:

Given that,

Charge,
`q=-4.77* 10^(-9)\ C`

We need to find the electric field at a point 0.3 m to the right of the charge.

We know that the electric field at a distance r is given by :

`E=(kq)/(r^2)\\\\E=(9* 10^9* 4.77* 10^(-9))/((0.3)^2)\\\\E=-477\ N/C`

So, the electric field is -477 N/C.