Answer:
The torque produced is 9.8 Nm.
Step-by-step explanation:
Given;
mass of the bucket filled with water, m = 20 kg
radius of the cylinder, r = 0.05 m
The torque produced by the weight of water and bucket is the product of force and the perpendicular distance from a point on the line of action of the applied force. (since the cylinder is not permitted to rotate).
τ = F x r
τ = (mg) x r
τ = (20 x 9.8) x 0.05
τ = 9.8 Nm
Therefore, the torque produced is 9.8 Nm.