Question

Two boulders have masses of 7.5 x 106 kg and 9.2 x 105 kg. After rolling apart, their centers are separated by a distance of 124 m. Find the gravitational attraction FG between them.

Answer 1

0.3 N

Step-by-step explanation:

Plug in all your variables:

6.67 ⋅ 10^-11 (7.5 ⋅ 10^6) (9.2 ⋅ 10^5)

--------------------------------

(124)^2

Once you plugin, You start to multiple solving to solve your problem:

460.23

---------- = 0.02993171 N

15376

Now Simplify:

Answer = 0.03 N

Answer 2

0.0299 N

Step-by-step explanation:

Applying,

F = Gmm'/r²................... Equation 1

Where F = gravitational force between the boulders, m = mass of the first boulder, m' = mass of the second boulder, r = distance between the boulders, G = Universal constant.

From the question,

Given: m = 7.5×10⁶ kg, m' = 9.2×10⁵ kg, r = 124 m

Constant: G = 6.67×10⁻¹¹ Nm²/kg²

Substitute these values into equation 1

F = (6.67×10⁻¹¹× 7.5×10⁶ × 9.2×10⁵ )/124²

F = (460.23)/15376

F = 0.0299 N