Question

1. If 80.0 ml of 3.00 M HCl is used to make a 100. ml of dilute acid, what is the molarity

of new dilute HCl solution?

Answer 1

We are given:

M1 = 3 Molar V1 = 80 mL

M2 = x Molar V2 = 100 mL

Finding the molarity:

We know that:

M₁V₁ = M₂V₂

where V can be in any units

(3)(80) = (x)(100)

x = 240/100 [dividing both sides by 100]

x = 2.4 Molar