Question

1.How many moles of each element are in 0.0250 mol of K 2 Cr O 4?

2. How many moles of ammonium ions are in 4.50 mol of (N H 4 ) 2 CO 3 ?

Please explain with all the process and answers

Answer 1

1. In 0.0250 moles of potassium chromate there are 0.05 moles of potassium , 0.025 moles of chromium and 0.1 moles of oxygen are present.

2. In 4.50 moles of ammonium carbonate there are 9 moles of ammonium ions and 4.5 moles of carbonate ions are present.

Step-by-step explanation:

1.

Moles of potassium chromate = 0.0250 mol

Formula of potassium chromate =
`K_2CrO_4`

1 mole of potassium chromate has 2 moles of potassium , 1 mole of chromium and 4 moles of oxygen.

Then in 0.0250 moles of potassium chromate:

Moles of potassium will be:

`2* 0.0250 mol= 0.05 mol`

Moles of chromium will be:

`1* 0.0250 mol= 0.025 mol`

Moles of oxygen will be:

`4* 0.0250 mol= 0.1 mol`

2.

Moles of ammonium carbonate = 4.50 mol

Formula of ammonium carbonate =
`(NH_4)_2CO_3`

1 mole of ammonium carbonate has 2 moles of ammonium ion and 1 mole of carbonate ion.

Then in 4.50 moles of ammonium carbonate:

Moles of ammonium ion will be:

`2* 4.50 mol= 9mol`

Moles of carbonate ions will be:

`1* 4.50 mol= 4.5 mol`