Question

When Victoria goes bowling, her scores are normally distributed with a mean of 130

and a standard deviation of 11. What is the probability that the next game Victoria
bowls, her score will be between 123 and 130, to the nearest thousandth?

Answer 1

0.2377 or about a 23.77% chance

Explanation:

P(123<X<130) = normalcdf(123,130,130,11) = 0.2377303466 ≈ 0.2377

Therefore, the probability that the next game Victoria bowls, her score will be between 123 and 130 is 0.2377 or about a 23.77% chance