Question

If you have 2 Moles of C3H6 and 10 Moles of O2, which reactant is limiting the following reaction: 2C3H6 + 9O2 → 6CO2 + 6H2O?

CO2
H2O
C3H6
O2

Answer 1

The limiting reactant is propene,
`C_3H_6`.

Step-by-step explanation:

`2C_3H_6 + 9O_2 \rightarrow 6CO_2 + 6H_2O`

Moles of nitrogen propene = 2 mol

Moles of oxygen = 10 mol

According to reaction, 2 moles of propene reacts with 9 moles of oxygen gas, then 2 moles of propene will react with:

`=(9)/(2)* 2mol=9\text{mol of oxygen gas}`

According to the question, we have 10 moles of oxygen gas, which is more than 9 moles of oxygen gas. This indicates that propene is present in a limiting amount hence, it is a limiting reactant.

The limiting reactant is propene, hence the correct answer is the
`C_3H_6`.