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Find the Area of the figure below, composed of an isosceles trapezoid and one

semicircle. Rounded to the nearest tenths place
10

Find the Area of the figure below, composed of an isosceles trapezoid and one semicircle-example-1
User Abulka
by
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1 Answer

5 votes

Answer:

Area of given figure = 48.28 unit² (Approx.)

Explanation:

Given:

Length of parallel lines are 10 , 4 respectively

Diameter of semi-circle = 4

Height of parallelogram = 6

Find:

Area of given figure

Computation:

Radius of semi-circle = Diameter of semi-circle / 2

Radius of semi-circle = 4 / 2

Radius of semi-circle = 2

Area of given figure = [1/2][Sum of parallel line][Height] + [πr² / 2]

Area of given figure = [1/2][10 + 4][6] + [(3.14)(2)² / 2]

Area of given figure = [1/2][14][6] + [(3.14)(4)/ 2]

Area of given figure = 42 + 6.28

Area of given figure = 48.28 unit² (Approx.)

User Avneesh Agrawal
by
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