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A simple random sample of 6,250 history majors at U.S. universitites was taken. Almost all of them could correctly name Abraham Lincoln's second Vice President, but only 11.3% of them knew his first Vice President. If possible, find a 95%-confidence interval for the percentage of history majors at U.S. universities who knew Abraham Lincoln's first Vice President. If this is not possible, why not

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Answer:

The 95%-confidence interval for the percentage of history majors at U.S. universities who knew Abraham Lincoln's first Vice President is (10.5%, 12.1%).

Explanation:

In a sample with a number n of people surveyed with a probability of a success of
\pi, and a confidence level of
1-\alpha, we have the following confidence interval of proportions.


\pi \pm z\sqrt{(\pi(1-\pi))/(n)}

In which

z is the z-score that has a p-value of
1 - (\alpha)/(2).

6250 students, 11.3% knew Abraham Lincoln's first vice-president.

This means that
n = 6250, \pi = 0.113

95% confidence level

So
\alpha = 0.05, z is the value of Z that has a p-value of
1 - (0.05)/(2) = 0.975, so
Z = 1.96.

The lower limit of this interval is:


\pi - z\sqrt{(\pi(1-\pi))/(n)} = 0.113 - 1.96\sqrt{(0.113*0.887)/(6250)} = 0.105

The upper limit of this interval is:


\pi + z\sqrt{(\pi(1-\pi))/(n)} = 0.113 + 1.96\sqrt{(0.113*0.887)/(6250)} = 0.121

As percentages:

0.105*100% = 10.5%

0.121*100% = 12.1%

The 95%-confidence interval for the percentage of history majors at U.S. universities who knew Abraham Lincoln's first Vice President is (10.5%, 12.1%).

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