Question

What is the twelfth term in the sequence 13, 26, 39, …?

A. 39
B. 52
C. 156
D. 166

Answer 1

• 156

Explanation:

Given the sequence

• 13, 26, 39, …

We see it is an AP with

• The first term a = 13
• Common difference d = 13 ( as 26 - 13 = 39 - 26 = 13)

The 12th term is:

• a₁₂ = a + 11d = 13 + 11*13 = 156