177k views
3 votes
If the actual concentration of the HCl was 0.33M what is your percent error?

User Tim Hofman
by
5.0k points

2 Answers

5 votes

Final answer:

The percent error can be calculated using the given formula when the actual and experimental values are known.

Step-by-step explanation:

The actual concentration of the HCl is given as 0.33M. The percent error can be calculated using the formula:

Percent Error = [(Actual Value - Experimental Value) / Actual Value] x 100%

In this case, the experimental value is the concentration of HCl that was found through the titration. Let's assume the concentration found through the titration is X M. The percent error can then be calculated as:

Percent Error = [(0.33 - X) / 0.33] x 100%

This formula can be used to find the percent error when the actual and experimental values are known.

User Rougepied
by
5.6k points
5 votes

Answer:

The appropriate solution is "6.818".

Step-by-step explanation:

The given value is:

Concentration of HCl (Actual value),

= 0.33 M

Concentration of HCl (Experimental value),

= 0.3515 M

Now,

The percentage error (%) will be:

=
(Experimental \ value-Actual \ value)/(Actua \ value)* 100

On substituting the given values, we get

=
(0.3532-0.33)/(0.33)* 100

=
(0.0225)/(0.33)* 100

=
0.06818* 100

=
6.818

User Michael Klenk
by
5.2k points