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Triangle D E F is shown. Angle D E F is 90 degrees and angle F D E is 42 degrees. The length of D E is 7.2 and the length of E F is d.

What is the value of d to the nearest hundredth?

User Ahyoung
by
5.3k points

2 Answers

7 votes

Answer:

i just checked, the guy above me is correct : 6.48

Explanation:

edge 2021

User Stefan Dochow
by
4.2k points
6 votes

Answer:

The value of the d is 6.48

Explanation:

The value of the d is 6.48, if the angle D E F is 90 degrees and angle F D E is 42 degrees and the length of D E is 7.2 and the length of E F is d.

Step-by-step explanation:

The given is,

Angle D E F is 90 degrees

Angle F D E is 42 degrees

The length of D E is 7.2

The length of E F is d

Step:1

For the given values,

Triangle DEF is right angle triangle,

Ref the attachment,

Angle FDE, ∅ = 42°

DE = 7.2

EF = d

Trigonometric ratio for the given right angle triangle,

∅ =

∅ =

( the value of tan 42° = 0.900404 )

EF = d = 6.48

Result:

The value of the d is 6.48, if the angle D E F is 90 degrees and angle F D E is 42 degrees and the length of D E is 7.2 and the length of E F is d.

User Andrew Khmylov
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4.2k points