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39 votes
39 votes
When the volume of a gas is

changed from m3 to 15.5 m3
the temperature will change from
159 K to 456 K.
Assume that the number of moles and the
pressure remain constant.

When the volume of a gas is changed from m3 to 15.5 m3 the temperature will change-example-1
User Ivan Bohannon
by
2.7k points

1 Answer

21 votes
21 votes

Charles law states that there is a directly proportional relationship between the volume and the temperature of the gas at certain pressure.

Therefore,

V1/T1 = V2/T2

V1 is unknown

T1 = 159K

V2 = 15.5m3

T2 = 456K

V1/159 = 15.5/456

V1 = (15.5*159)/456 = 5.404m3.

When the volume of a gas is changed from 5.404 m3 to 15.5 m3 the temperature will change from 159 K to 456 K.

User Venkatesh Somu
by
3.0k points