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An article measured speeds of vehicles on several roads in the state of Kansas. On South Cedar Niles, 73 vehicles were observed, and 45 of them were exceeding the speed limit. Can you conclude that more than 60% of the vehicles on South Cedar Niles exceed the speed limit

User Researcher
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1 Answer

2 votes

Answer:

The
p- value is
0.2996.

Explanation:

This is a right-tailed test.

The null and alternative hypothesis is


H_0:p=0.60\\H_a:p>0.60

Point estimate
= sample proportion
=\hat{P}=x/n=0.630

Test statistics


$z=\left(\hat{p}-p_(0)\right) / √(p)_(0^(*))\left(1-p_(0)) / n\right.$\\$=(0.630-0.60) / √((0.60 * 0.40) / 73)$\\$=0.526$\\P-value $=P(Z>z)$\\$=0.2996$\\The $\mathrm{P}$ -value is $0.2996$

User Timborden
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