Question

Solve the equation using the quadratic formula

2n^2+3n=-54

a) {4,-9}
b) {6,-2}
c) {9,-3}
d) {-4 1/2, 6}

Answer 1

Explanation:

Rewrite this quadratic equation in standard form: 2n^2 + 3n + 54 = 0. Identify the coefficients of the n terms: they are 2, 3, 54.

Find the discriminant b^2 - 4ac: It is 3^2 - 4(2)(54), or -423. The negative sign tells us that this quadratic has two unequal, complex roots, which are:

-(3) ± i√423 -3 ± i√423

n = ------------------- = ------------------

2(2) 4