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Which equation has the same solutions as 2x^2+x-3 = 0?

1. (2x - 1)(x + 3) = 0
2. (2x + 1)(-3) = 0
3. (2x - 3)(x+1)=0
4. (2x+3)(x - 1) = 0​

1 Answer

6 votes

Answer:

given solution


2x^2+x-3 = 0

first one


{2x}^(2) - 6x - x - 3 = 0

second one


- 6x - 3 = 0

third one


{2x}^(2) + 2x - 3x - 3 = 0

fourth one


{2x}^(2) + 3x - 2x - 3 = 0

Explanation:

fourth answer is suite for this given solution

answer is 4. (2x+3)(x - 1) = 0

good luck

User Rethab
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