Answer:
We have
n[T]=4+20-x+x+23-x
32=47-x
x=47-32
x=15
so
the number of men questioned who have
the number of men questioned who haveall three characteristics is 15.
again
n[S]=6+20-x+x+24-x=50-x=50-15=35
again
we have
n[U]=n[T]+n[s]+N only [ B]
54=32+35+N only [ B]-n[T and S]
N only [ B]=54-67+20=7
who are bald but
who are bald butnot tall a slim is 7.