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__Mg + __02 = __Mgo a). 2, 2, 1 b). 2, 1,2 c). 2, 1, 1 d). 2, 2,2
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__Mg + __02 = __Mgo
a). 2, 2, 1
b). 2, 1,2
c). 2, 1, 1
d). 2, 2,2

User Annmarie
by
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1 Answer

1 vote
The answer is b). 2,1,2

you’re welcome :)
__Mg + __02 = __Mgo a). 2, 2, 1 b). 2, 1,2 c). 2, 1, 1 d). 2, 2,2-example-1
User Erwinheiser
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