Question

Given 23 g of potassium nitrate per 25 g of water, what temperature should create a saturated solution?

Answer 1

At about 51 °C

Step-by-step explanation:

Hello there!

In this case, according to the attached solubility chart of potassium nitrate, our first step for this problem is to calculate the grams of this solute in 100 g given that 23 g are soluble in 25 g of water:

`(23g)/(25g)=(x)/(100g)\\\\x= (23g*100g)/(25g)=92g`

Thus, such solubility of 92 g in 100 g of water is exhibited at about 51 °C.

Regards!