Question

You know that for any object to escape the gravitational pull of a planet, star, and so on, the object must first achieve escape velocity, or vesc. What velocity must the Veracious achieve to escape Earth

Answer 1

11.186 * 10^3 m/s

Step-by-step explanation:

For a Veracious to escape the gravitational pull of the earth it has to a attain

Vesc =
`\sqrt{(2GM)/(R) }` -------- ( 1 )

where: G = ( gravitational constant ) = 6.674 * 10^-11 m^3 kg^-1 s^-2 )

M = ( mass of earth) = 5.972 * 10^24 kg

R = ( Radius of earth ) = 6.371 * 10^6 m

next we will Input values into equation ( 1 )

The required Vesc that the Veracious can attain to escape the gravitational pull of the earth = 11.186 * 10^3 m/s