Answer:
13.1 m/s
Explanation: Given that a pendulum that was originally erected by Foucault at the Pantheon in Paris for the Paris Exhibition in 1851 was restored in 1995. It has a 28.0 kg sphere suspended from a 67.0-m light cable. If the amplitude of the swing is 5.00 m, what is the maximum speed of the sphere
The formula to use is :
W = sqrt ( L/g )
Where
L = 67m
g = 9.8m/s^2
A = 5m
Substitute all the parameters into the formula
W = sqrt ( 67 / 9.8 )
W = 2.6
To get the maximum velocity, we use the below formula.
V = wA
V = 2.6 × 5
V = 13.07 m/s
Therefore the maximum speed of the sphere is 13.1 m/s approximately.