Question

If two proton approach each other with speed of 400m\s and 450m\s respectively what is the total momentum of the two particle system

Answer 1

Answer:
`83.65* 10^(-27)\ kg.m/s`

Step-by-step explanation:

Given

The velocities of the protons are 400 m/s and 450 m/s

Mass of the Proton is
`m=1.673* 10^(-27)\ kg`

Since they travel in the opposite direction, therefore, their momentum cancels out each other.

Momentum is the product of mass and velocity

`\therefore m(450-400)\\\Rightarrow 1.673* 10^(-27)* 50\\\Rightarrow 83.65* 10^(-27)\ kg.m/s`

The direction of momentum is in the direction of proton having 450 m/s velocity.