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If one mol of gas = 22.4 at STP how many liters is occupied by 3.65 moles of oxygen gas at STP
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If one mol of gas = 22.4 at STP how many liters is occupied by 3.65 moles of oxygen gas at STP

User Nndru
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1 mole gas at STP = 22.4 L

so volume of oxygen at STP:


\tt = 3.65* 22.4~L=81.76~L

User Tom Ritter
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