Question

If we dcrease the radius of each cylinder by 2m , which one has the greater volume give your answer rounded to the nearest tenth use 3.14 for pi

Answer 1

See Explanation

Explanation:

Given

The question is incomplete, as the cylinders are not given.

Required

The cylinder with greater volume

To answer this question, I will assume the following dimensions.

Cylinder 1

`r = 5`

`h = 10`

Cylinder 2

`r = 7`

`h = 5`

Volume is calculated as:

`V = \pi r^2h`

When the radius is reduced by 2, the formula becomes

`V = \pi (r - 2)^2h`

For the first cylinder, we have:

`V_1 = \pi (r - 2)^2h`

`V_1 = 3.14 * (5 - 2)^2 * 10`

`V_1 = 3.14 * 3^2 * 10`

`V_1 = 3.14 * 9 * 10\\`

`V_1 = 282.6`

For the second cylinder, we have:

`V_2 = \pi (r - 2)^2h`

`V_2 = 3.14 * (7 - 2)^2 * 5`

`V_2 = 3.14 * 5^2 * 5`

`V_2 = 3.14 * 25 * 5`

`V_2 = 392.5`

Cylinder 2 has a greater volume because 392.5 > 282.6

Note: Irrespective of the dimension of the cylinders, the above step works fine.