Question

What is the 31st term in the sequence 204,200,196

Answer 1

a(31) = 84

Explanation:

The first term, a(1) is 204, and the common difference is 4. That is, each new term is 4 less than the previous term.

The rule governing this arithmetic sequence is

a(n) = 204 - 4(n - 1)

and so the 31st term is

a(31) = 204 - 4(30) = 84