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Can someone please give me the (Answers) to this? ... please ...

I need help….

Can someone please give me the (Answers) to this? ... please ... I need help….-example-1

2 Answers

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Answer:

above is the answer to the question

Can someone please give me the (Answers) to this? ... please ... I need help….-example-1
User Tony Barnes
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7. Triangles KJL similar to Triangle QPR


(KJ)/(LJ) =(QP)/(RP) \\(KJ)/(28) =(33)/(42) \\KJ = (33)/(42) *28 =22

8. Triangles KML similar to Triangle VTU


(UT)/(UV) =(LM)/(LK) \\(UT)/(60) =(117)/(130) \\UT =(117)/(130) *60\\UT=54

Last question: Triangle CUB similar to TUS

  • if both triangles are similar then the side lengths are equally

proportional

  • For the picture, we see that TU is three times as long as CU
  • therefore SU is three times as long as BU, and since SU is 12 then BU is 4. Therefore SB is 8
User Nicolas HENAUX
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