Answer:
The perimeter of the rectangle is expressed as;
![P = (72 \ + \ 2W^2)/(W)](https://img.qammunity.org/2022/formulas/mathematics/high-school/pykuwic1pg9lp2ltlypbhmc53ehes95xsr.png)
Explanation:
Given;
area of the rectangle, A = 36 cm²
width of the rectangle, = W
Let L represent the length of the rectangle,
A = L x W
![L = (A)/(W) = (36)/(W)](https://img.qammunity.org/2022/formulas/mathematics/high-school/2ikk0dm4a8rhkt4huz0sxekqkntj5nvs7y.png)
The perimeter of the rectangle is calculated as;
P = 2(L + W)
Substitute the value of L into the above equation;
![P = 2(L + W)\\\\P = 2 ((36)/(W) + W)\\\\P = 2 ((36 + W^2)/(W) )\\\\P = (72 \ + \ 2W^2)/(W)](https://img.qammunity.org/2022/formulas/mathematics/high-school/25moq3nhe8hbfq41eq827h03kauuaaft2m.png)
Thus, the perimeter of the rectangle is expressed as
![P = (72 \ + \ 2W^2)/(W)](https://img.qammunity.org/2022/formulas/mathematics/high-school/pykuwic1pg9lp2ltlypbhmc53ehes95xsr.png)