150k views
4 votes
A consumer group claims that the average annual consumption of high fructose corn syrup by a person in the U.S. is 48.8 pounds. You believe it is higher. You take a simple random sample of 35 people in the U.S. and find an average of 53.8 pounds with a standard deviation of 4.4 pounds. Test at 1% significance. Round to the fourth

User Vink
by
3.9k points

1 Answer

6 votes

Answer:


6.7159

Explanation:


\mu=48.8\\n=35\\\bar{x}=53.8\\\sigma=4.4\\\alpha=1\%=0.01

Null and alternative hypothesis :


H_0:\mu=48.8\\H_a:\mu>48.8

Test statistic,


t=\frac{\bar{x}-\mu}{(\sigma)/(√(n))}


\Rightarrow t=(53.8-48.8)/((4.4)/(√(35)))


\Rightarrow t=(5* 5.91)/(4.4)


\Rightarrow t=6.715

Test statistic
t=6.715


P-value
=P(t>6.715)


P- value
=0.0001 by the p- table

Significance level
0.01


p-value
<0.01

We reject
H_0

User ElDuderino
by
4.4k points