Question

If 35 mL of a .5 m hydrochloric acid solution is required to neutralize 15 mL of a sodium hydroxide solution of unknown concentration, what is the molarity of the sodium hydroxide solution

Answer 1

Answer: The molarity of the sodium hydroxide solution is 1.16 M.

Step-by-step explanation:

Given:
`V_(1)` = 35 mL,
`M_(1)` = 0.5 M

`V_(2)` = 15 mL,
`M_(2)` = ?

Formula used to calculate the molarity of the sodium hydroxide solution is as follows.

`M_(1)V_(1) = M_(2)V_(2)`

Substitute the values into above formula as follows.

`M_(1)V_(1) = M_(2)V_(2)\\0.5 M * 35 mL = M_(2) * 15 mL\\M_(2) = (0.5 M * 35 mL)/(15 mL)\\= 1.16 M`

Thus, we can conclude that the molarity of the sodium hydroxide solution is 1.16 M.