191k views
3 votes
When you fill your coffee at a gas station, you're supposed to get 8 ounces of coffee with a standard deviation of .7 ounces. A random sample of 50 "8 ounce" coffees is collected and measured and the mean was found to be 7.8 ounces.

User Gooseman
by
8.5k points

1 Answer

3 votes

Answer:

The answer is below

Explanation:

When you fill your coffee at a gas station, you're supposed to get 8 ounces of coffee with a standard deviation of .7 ounces. A random sample of 50 "8 ounce" coffees is collected and measured and the mean was found to be 7.8 ounces. a) Find a 90% confidence interval. b) Interpret the confidence interval in the context.

Solution:

The confidence = 90% = 0.9, mean (μ) = 7.8 ounces, standard deviation (σ) = 0.7 ounces, sample size (n) = 50

α = 1 - C = 1 - 0.9 = 0.1

α/2 = 0.1 / 2 = 0.05

The z score of α/2 is the same as the z score of 0.45 (0.5 - 0.05) which is equal to 1.65

The margin of error (E) is given by:


E = z_(\alpha)/(2) *(\sigma)/(√(n) ) \\\\E=1.65*(0.7)/(√(50) ) =0.16

The confidence interval = μ ± E = 7.8 ± 0.16 = (7.64, 7.96)

b) This means that we are 90% confident that any selected coffee has a weight between 7.64 ounce to 7,96 ounce

User Joe Cannatti
by
8.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories