Answer:
θ₁ = 140º, θ₂ = -40º
Step-by-step explanation:
For this exercise we must use Malus's law
I = Io cos² θ
where the angle is between two polarizers.
When the non-polarized light reaches the first polarized light, the vertically polarized light passes
I₁ = I₀ / 2
This light reaches the second polarizer and the light that comes out of this polarizer must reach the third polarized one, it is requested that no light comes out of it, for which the polarizer B must be at 90º from the third, so the possible angles are
θ₁ = 50 + 90 = 140º
θ₂ = 50 - 90 = -40º