Question

A crate (m = 100 kg) is pulled across a floor to the right with a rope horizontal to the floor. The tension in the rope is 400 N. The coefficient of kinetic friction is 0.4. What is the acceleration? If started from rest, what was the velocity after 3 seconds?

Answer 1

Step-by-step explanation:

Force of friction acting on the crate = μ mg

= .4 x 100 x 9.8 = 392 N

Net force acting on the crate = 400 -392 N = 8 N .

acceleration = net force / mass

= 8 N / 100 kg

= .08 m /s²

velocity after 3 s.

v = u + at

= 0 + .08 x 3

= 0.24 m/s .