Question

What are the roots of the quadratic equation below?
2x2 + 12x + 11 = 0

Answer 1

[see below]

Explanation:

Assuming that the equation is:

`2x^2+2x+11=0`

I graphed the given equation on a graphing calculator.

The roots of a quadradic equation are the x-intercepts of the function.

On the graph the parabola intercepts the points (-4.871, 0) and (-1.129, 0).

Therefore, -4.871 and -1.129 are the roots to the equation.

If we used the quadradic formula...

`(-12\pm√(12^2-4*2*11) )/(2*2)\\\\(-12\pm2√(14) )/(4)\\\\(-12\pm2√(14) )/(4)\\\\\boxed{(-6\pm√(14) )/(2)}`

Hope this helps you.