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A high school soccer team is going to Columbus to see a professional soccer game. A coordinate grid is superimposed on a highway map of Ohio. The high school is at point (3, 4) and the stadium in Columbus is at point (7, 1). The map shows a highway rest stop halfway between the cities. What are the coordinates of the rest stop? What is the approximate distance between the high school and the stadium? (One unit = 6.4 miles.)

User SEU
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Answer:

a) The coordinates of the rest stop is
C(x,y) = \left(5, (5)/(2) \right).

b) The approximate distance between the high school and the stadium is 32 miles.

Explanation:

a) The rest stop is located in the midpoint of the line segment between the high school and the stadium. Vectorially speaking, we use the following formula:


C(x,y) = (1)/(2)\cdot A(x,y) + (1)/(2)\cdot B(x,y) (1)

Where:


A(x,y) - Coordinates of the high school.


B(x,y) - Coordinates of the stadium.


C(x,y) - Coordinates of the rest stop.

If we know that
A(x,y) = (3, 4) and
B(x,y) = (7,1), then the coordinates of the rest stop are, respectively:


C(x,y) = (1)/(2)\cdot (3, 4) + (1)/(2)\cdot (7, 1)


C(x,y) = \left((3)/(2), 2 \right) + \left((7)/(2), (1)/(2) \right)


C(x,y) = \left(5, (5)/(2) \right)

The coordinates of the rest stop is
C(x,y) = \left(5, (5)/(2) \right).

b) The approximate distance between the high school and the stadium (
d), in miles, is the product of the Length Equation of the Line Segment and the scale factor:


d = r\cdot \sqrt{(\Delta x)^(2) + (\Delta y)^(2)} (2)

Where:


r - Scale factor, in miles.


\Delta x,
\Delta y - Horizontal and vertical distances between the high school and the stadium, no unit.

If we know that
r = 6.4\,mi,
\Delta x = 4 and
\Delta y = -3, then the distance between the high school and the stadium is:


d = r\cdot \sqrt{(\Delta x)^(2) + (\Delta y)^(2)}


d = (6.4\,mi)\cdot \sqrt{4^(2)+(-3)^(2)}


d = 32\,mi

The approximate distance between the high school and the stadium is 32 miles.

User Andriy Lozynskiy
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