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The sum of David and Jacobs age is 39. Two years ago David was four times Jacobs age. How old are three now?

1 Answer

5 votes

Answer:

David is 30

Jacob is 9

Explanation:

The sum of David and Jacobs age is 39

d + j = 39

d = 39 - j

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Two years ago David was four times Jacobs age

(d - 2) = 4(j - 2)

d - 2 = 4j - 8

d = 4j - 6

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Set the equations equal

4j - 6 = 39 - j

5j = 45

j = 9

d = 4(9) - 6

d = 30

User Alexander Mashin
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