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A driver fills an 18.9L steel gasoline can with gasoline at 15.0°C right up to the top. He forgets to replace the cap and leaves the can in the back of his truck. The temperature climbs to 30.0°C by 1pm. How much gasoline spills out of the can​

2 Answers

2 votes

Final answer:

To determine how much gasoline spills from a can due to thermal expansion, calculate the volume changes of both the steel can and the gasoline as they are heated and subtract them. The substance with a larger coefficient of expansion (gasoline) will result in the overflow. The exact calculation requires the coefficients of expansion, which are not provided.

Step-by-step explanation:

To calculate how much gasoline spills out of the can due to thermal expansion when the temperature rises from 15.0°C to 30.0°C, we need to consider both the expansion of the steel can and the expansion of the gasoline itself. We use the coefficient of volume expansion for each material, with the formula ΔV = βVΔ0ΔT, where ΔV is the change in volume, β is the coefficient of volume expansion, VΔ0 is the initial volume, and ΔT is the change in temperature.

If we had the coefficients of expansion for steel and gasoline, we would first calculate the change in volume of the gasoline, and then the change in volume of the steel can. The amount of gasoline that spills out would be the difference between these two volumes. However, since we do not have the exact coefficient values in this example, we cannot perform the calculation. In a real-world scenario, we can assume that gasoline would spill out because it generally has a higher coefficient of volume expansion compared to solid materials like steel, leading to a greater increase in volume with temperature.

It is important to note that this example is similar to the scenario provided where 60.0 L of gasoline at 15.0°C expands to 61.1 L when it warms to 35.0°C. This implies that gasoline has a significant thermal expansion that often causes spillage if a tank is filled to the brim on a cool day and then heated.

User Edo Akse
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4 votes

Answer:

ΔV = 0.98 L

Step-by-step explanation:

First, we will calculate the increased volume using Charles' Law:


(V_1)/(T_1) = (V_2)/(T_2)

where,

V₁ =initial volume = 18.9 L

V₂ = final volume = ?

T₁ = initial temperature = 15°C + 273 = 288 k

T₂ = final temperature = 30°C + 273 = 303 k

Therefore,


(18.9\ L)/(288\ k) = (V_2)/(303\ k)

V₂ = 19.88 L

Now, we calculate the change in volume:

ΔV = V₂ - V₁ = 19.88L - 18.9 L

ΔV = 0.98 L

This is the volume of gasoline that will spill out.

User Sreeraj VR
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4.4k points