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Log (w2+21) - log (10)

1 Answer

3 votes

Answer:


w =7\ or\ w =3

Explanation:

Given

The right question is:


\log(w^2+ 21) = \log(10w)

Required

Solve for w


\log(w^2+ 21) = \log(10w)

Cancel log on both sides


w^2+ 21 = 10w

Equate to 0


w^2 - 10w+ 21 = 0

Split


w^2 - 3w - 7w+ 21 = 0

Factorize


w(w - 3) - 7(w-3) = 0

Factor out w - 3


(w - 7)(w-3) = 0

Solve for w


w - 7 = 0\ and\ w - 3 = 0


w =7\ or\ w =3

User GerardBeckerleg
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