Given:
The table of values.
To find:
Whether the given table is a proportional or non proportional relation.
Solution:
If y is proportional to x, then
![y\propto x](https://img.qammunity.org/2022/formulas/mathematics/high-school/62381d1lgl4gts59qc4ifjfh7w6p0chv68.png)
![y=kx](https://img.qammunity.org/2022/formulas/mathematics/high-school/8msakxrmy3330hdr5nt3xfq5l60qweogpv.png)
![(y)/(x)=k](https://img.qammunity.org/2022/formulas/mathematics/high-school/ea6u270m0q9trgufd5o6uyal578ex39mvw.png)
Where, k is the constant of proportionality.
Find the value of k for each ordered pairs in table. If the value of k is constant, then the relation is proportional.
The ordered pairs from the table are (10,18), (11, 18.6), (12,19.2). The values of k for each ordered pair is:
![(18)/(10)=1.8](https://img.qammunity.org/2022/formulas/mathematics/high-school/sht4witeyoycetxcdq9ptqrrzi2bzs32dn.png)
![(18.6)/(11)\approx 1.69](https://img.qammunity.org/2022/formulas/mathematics/high-school/c7zb8wr9nn84rg8rkia1j4xa744ci6i4nz.png)
![(19.2)/(12)=1.6](https://img.qammunity.org/2022/formulas/mathematics/high-school/u9zcdgnqbai26u9awx9f9i872iye94bol9.png)
Since the value of k is not constant, therefore the given table represents a non proportional relationship.