Question

What is the pressure of a car tire that had an initial pressure of 33.7 kPa but was

heated from 98.4°C to 110.°C?

Answer 1

34752.6 Pa.

Step-by-step explanation:

Applying,

P/T = P'/T'............... Equation 1

Where P = Initial Pressure, T = Initial Temperature, P' = Final pressure, T' = Final temperature.

make P' the subject of the equation

P' = (PT'/T).............. Equation 2

From the question,

Given: P = 33.7 kPa = 33700 Pa, T = 98.4°C = (273+98.4) = 371.4 K, T' = (110+273) = 383 K

Substitute these values into equation 2

P' = (33700×383)/371.4

P' = 34752.6 Pa.