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A 6,600 kg train car moving at +2.0 m/s bumps into and locks together with one of mass 5,400 kg moving at −3.0 m/s . What is their final velocity? −1.0 m/s −0.25 m/s +0.50 m/s +2.5 m/s
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1 vote
A 6,600 kg train car moving at +2.0 m/s bumps into and locks together with one of mass 5,400 kg moving at −3.0 m/s . What is their final velocity?

−1.0 m/s

−0.25 m/s

+0.50 m/s

+2.5 m/s

User Mao
by
4.9k points

1 Answer

3 votes

Answer:

option B is the correct option

Step-by-step explanation:

According to momentum conversion,

momentum of one car= 6600×2=13,200kgm/s

momentum of another car=5,400×(-3)=16,200kgm/s

Then,

Momentum of second car-momentum of first car

=16,200-13200

=3000kgm/s

mass of first car -mass of second car

=6600-5400

=600kg

final velocity=3000/600=2.5 m/s

User Marabol
by
4.5k points
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